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用途：方便js操作查询json数据。
下载网址：
使用方法：只需要引用linq.js即可。
查询方法：
一、where查询
| 1 2 3 4 5 6 7 8 | var myList = [ { Name: "Jim" , Age: 20 }, { Name: "Kate" , Age: 21 }, { Name: "Lilei" , Age: 18 }, { Name: "John" , Age: 14 }, { Name: "LinTao" , Age: 25 } ]; var arrRes = Enumerable.From(myList).Where( "x=>x.Name=='Jim'" ).ToArray(); |
二、排序：OrderBy
| 1 2 3 4 5 6 7 8 | var myList = [ { Name: "Jim" , Age: 20 }, { Name: "Kate" , Age: 21 }, { Name: "Lilei" , Age: 18 }, { Name: "John" , Age: 14 }, { Name: "LinTao" , Age: 25 } ]; var arrRes = Enumerable.From(myList).OrderBy( "x=>x.Age" ).ToArray(); //降序OrderByDescending() |
三、去重：Distinct
| 1 2 3 4 5 6 7 8 | var myList = [ { Name: "Jim" , Age: 20 }, { Name: "Kate" , Age: 20 }, { Name: "Lilei" , Age: 20 }, { Name: "John" , Age: 14 }, { Name: "LinTao" , Age: 25 } ]; var arrRes = Enumerable.From(myList).Distinct( "x=>x.Age" ).ToArray(); |
四、遍历：ForEach
| 1 2 3 4 5 6 7 8 9 10 | var myList = [ { Name: "Jim" , Age: 20 }, { Name: "Kate" , Age: 20 }, { Name: "Lilei" , Age: 20 }, { Name: "John" , Age: 14 }, { Name: "LinTao" , Age: 25 } ]; Enumerable.From(myList).ForEach( function (value, index){ document.write( "值=" +value+ ",索引=" +index); }); |
五、取唯一对象：First、FirstOrDefault、Last、LastOrDefault、Single、SingleOrDefault
| 1 2 3 4 5 6 7 8 | var myList = [ { Name: "Jim" , Age: 20 }, { Name: "Kate" , Age: 20 }, { Name: "Lilei" , Age: 20 }, { Name: "John" , Age: 14 }, { Name: "LinTao" , Age: 25 } ]; var arrRes = Enumerable.From(myList).FirstOrDefault( "x=>x.Age>18" ); |
六、Skip、Take
| 1 2 | Enumerable.Range(1,10).Skip(5) //结果[6,7,8,9,10] Enumerable.Range(1,10).Take(5) //结果[1,2,3,4,5] |
本文转自王磊的博客博客园博客，原文链接：http://www.cnblogs.com/vipstone/p/5588020.html，如需转载请自行联系原作者